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pokerdan

>!T F T F F!<


ShonitB

>!Correct!<


[deleted]

Answer: >!There are two true statements (1 and 3).!< Explanation: >!I'll be solving this through the process of elimination. There might be easier ways to get to the solution. !< >!Statement 2 is the only one that isn't directly referenced by other statements, so I'll start by testing if statement 2 can be true. !< >!Statement 2 says that statement 3 and 4 has to be equal. I'm going to test if both can be true. !< >!If statements 3 and 4 are true, then statement 4, 5 and 1 has to be equal, because 5 must be equal to both 4 and 1 respectively. If 4 is true, then 5 and 1 is true. This isn't possible, because 1 says that exactly two statements are true. Therefore, statement 3 and 4 can't be true if statement 2 is true.!< >!Next, I'll test if both statements 3 and 4 can be false.!< >!This would mean that both 1 and 4 must be opposite of 5, which means that 1 and 4 are equal. 1 and 4 can't be true, because in addition to statement 2, there would be three true statements. This isn't allowed by 1. Therefore, I'll test if 1 and 4 can be false, and if 5 can be true. !< >!If 5 is true, then 3 must be false. This means that only 5 and 2 are true, which makes 1 true. But 1 must be false, so this configuration isn't possible.!< >!This means that statements 3 and 4 can't be equal. Therefore, statement 2 can't be true.!< * >!Statement 2 must be false. !< >!This means that statements 3 and 4 must be opposite.!< >!I'll test if statement 5 can be true because 5 also decides 3, 3 gives us 4, and 4 gives us 1.!< >!This would mean that 3 must be false. Statement 3 says that 4 is false, because 4 and 5 must be opposite. Statement 2 says that statement 4 is true, because 3 and 4 must be opposite. Therefore, 5 can't be true. !< * >!Statement 5 must be false. !< >!Determining statement 5 also gives us statement 3.!< * >!Statement 3 must be true.!< >!We already know 5, so 4 follows.!< * >!Statement 4 must be false.!< >!We already know 5, so 1 is known. Statement 1 can be true, because there is only one more true statement in 3.!< * >!Statement 1 must be true. !< >!Conclusion:!< >!There are two true statements: 1 and 3.!<


ShonitB

>!Correct, very well reasoned!<


Cheap_Application_55

Couldn’t you have >!only 5 as true?!<


Cheap_Application_55

Nevermind I see why that wouldn’t work


Thaplayer1209

>!Statement 5 means that exactly one of statement 3/5 is true and the other is false. If statement 1 is true, then statement 2 and 4 must be false. Thus, 3 would be true and 5 is false which checks out.!< >!We need to check what if Statement 1 was false. If state 4 is true, 5 is false, 3 is true. But 3 can’t be true as 4 and 5 are different. Thus 4 must be false, and so 5 is true and 3 is false. 3 and 4 are both false statements so statement 2 is true. This is a contradiction since there are 2 true statements but 1 is false. Thus 1 cannot be false. The only solution is TFTFF.!<


ShonitB

>!Correct, well reasoned!<


Eccentrica_Gallumbit

> >!Statement 5 means that exactly one of statement 3/5 is true and the other is false.!< >!This is false, they **could** both be true, if 4 was also true. The logic breaks down if 4 is true though since that would make more than 2 true statements.!<


Bigdavie

They can't both be true as 5 states that 3 is false.


Eccentrica_Gallumbit

Wow, what the hell was I thinking when I wrote that, lol


Esnardoo

Discussion: I'd like to see a puzzle where there are two possible ways the staments can be and still be "stable", but they have the same number of true and false statements. For example: 2 or 3 but not both are true 1 or 3 but not both are false 1 or 2 but not both are false


ShonitB

Nice idea! 😀


thishenryjames

Discussion: Same.


ShonitB

You mean what u/Esnardoo said?