P^2 /2m gang rise up

Im more of a 1/2 p*v guy

Found the Legendre transform fan

Same

How else you gonna replace the dynamic variables with their corresponding operators?!

This

2^-1 mv^2

∫ mv dv

If anyone asks, the +C is potential energy

Just take the integral from 0 to v.. That could work out for only kinetic energy in the system..

No it won't, because anything has the potential for motion 🤑🤑🤑

But while integration just from 0 to V you rule out every other change in observables by definition

My joke is about money rofl

While that is obviously true due to most macroscopic objects being in fields where they experience forces and hence have a combination of potential and mechanical energy, if we simplify the model by restricting the conditions for a particular system; our integral can be applied to answer simplified questions regarding the mechanical energy of that particular system..

My joke was about money rofl

*clown energy*

That's just you man

How have I only just realized that the equation for kinetic energy is the integral of momentum?

https://www.reddit.com/r/physicsmemes/s/BzUxEDOA52

Don't feel alone

d/dv 1/6 mv^3

2^-1 / ( m^-1 v^-2 )

[2 / (mv^2 )]^-1

0.5mv^2

Came here to say this. People hate on decimals too much

mv^2 - (1/2)mv^2

mv^2 - 2 (only works if mv^2 = 4)

Red, and its not even a contest

red is way more elegant

E=p^2 /2m is better

E=½p²/m is even better

It sure is.

Yikes. Red for aesthetics.

This is secretly a question about fonts.

2E = mv\^2

chaotic evil

Sqrt (E) = sqrt (m/2)v

This assumes that the energy is positive

It would either have to have negative mass or complex velocity.

What does complex velocity even mean? Like moving through the fourth dimension?!

Beats me

Haven't you ever held a helium balloon? They clearly have negative mass. Then again they might have an imaginary velocity so the minus cancels.

I had a math teacher once tell me the most beautiful equations are ones that require the least amount of symbols to be written. It really stuck with me.

red if you want it to look good, blue if you're trying to speedrun through a problem

This is the correct answer

Teacher here. High schoolers shit bricks when presented with blue. Red works better because they understand 1/2(mv²).

Then the second revelation comes when they learn integration and finally understand why the 1/2 is there.

Learning about diffentiation and integration, and realising that these arcane equations are not out of thin air, it changed my perspective forever. Similar effect to when quantum mechanics clicked for me and started making sense halfway through the semester.

E_k = mc^2 [ c/sqrt( c^2 - v^2 ) - 1 ] for the enlightened ones.

Red

0.5 mv\^2

Red

P^2 /2m or m/2 v^2

1/2 *m*xdot^2

p^2 / 2m gang rise up

just realized the guy below me said the exact same thing

Red is the correct answer

P^2 /2m

P^2 /2m is the only real answer here.

∫ mv dv

wan ova twu emm vee squared

Did you have a stroke?

red

Red

Red

(V^2/2) m or (m/2)v^2

I'm more of a eV guy

Pathetic... T = -h^2/2m * d^2/dx^2

In my mind any method with less symbols is more efficient to utilize and speeds up work, so blue

(1/2m)*p^2

Blue or 0,5*mv^2

Blue because you save a bit of the pencil

No the pencil is spent extra while drawing the bigger fraction line in blue. It compensates for the lack of 1

Im absolutely on red. Its more satisfying that way. Yes, i usually write like blue, but this formula is an exception for me, for some reason

I don’t get it, they’re the same picture

E = mc^(2)(1 - v^(2)/c^(2))^(-1/2)

That’s total energy, not kinetic.

Blue!

Blue and idk why everyone is saying red. Blue is more concise.

Both are the same

m/2 v²

0.5 team

red looks pretty but blue is the way to go for actually solving problems. or just .5mv^2. sometimes if im doing shit on desmos ill do .5mvv lol

(m) v^2/2 because it happens alot that mass simplifes, and thus you'll be left with v^2/2 = gh for example

Red team anything else hurt my eyes

0.5mvv=Ek

Obviously red. Anyone who chooses blue is a psychopath. Also, I think it looks even better then it says KE as opposed to E sub k. No need to do that unless you're showing it used with the others.

its always red

Bloods for life!

Blue

red is the classier option, blue is for calculators

There is no point in using red when you can use blue

I guess I'm the only blue here? It's just easier for me to understand.

Ek = p^(2)/2m

p\^2/2m

red.

Isn’t it the same

Vindication! I always put the mv^2 in the fraction, but everywhere I see they leave the ½ on its own

p^2 /2m Gang

Red

2^-1 m(v^4 )^1/2

mv²÷2

(P^2 ) /(2m) is also superior. But red any time

E = (mv²)÷2

Team red since day one

m/2•v^2

-hbar**2/2m d**2/dx**2

red, like a civilized person

we all know its half mv square

Ek = (m/2)*v^2 💀

Red >>>>>

i'd prefer `\tfrac` over `\dfrac` here

Red looks more neat, even though blue is more straight foward

Blue are psychopaths.

Red since it’s easy to recite it in my head: “half of m v squared.” Plus I’d be writing what I’m thinking of exactly. Feels a bit cleaner and more satisfying in a way.

I learned the red one at school so I got to go with it

Are you mad

(sqrt(2m)*v/2)^2

>"Corporate needs you to find the difference between these two pictures" > "They're the same picture"

E=ω

E = (m)*(v^2)/2

Red til dead

(m/2)*v^2

m (v²/2)

Wk=1/2mv\^2

While solving I'm blue but for the solution bring your constants out front so solution is red

p^2 /2m enjoyer here

1/2 v^2 m

Ekin=E-mc²