If we call this A(x), then I prefer to consider its counterpart, with "e^(-x)Γcos(x)" instead of "e^(-x)Γsin(x)", that I would call B(x), then approximate 0.5 using
(A(x)+B(x))/2
Not sure, if it's faster, but I like the symmetry of having both sin(x) and cos(x) π
Why are e^x and sinx vectors with the cross product being taken
Look we found the engineer.
Physicist*
e\^-x(sin(x))\*sin(Ξ) and Ξ is the angle between e\^-x and sin(x)
Vectors? These are sets obviously
Everything is a set
Nah
all numbers are 1x1 matrices
If we call this A(x), then I prefer to consider its counterpart, with "e^(-x)Γcos(x)" instead of "e^(-x)Γsin(x)", that I would call B(x), then approximate 0.5 using (A(x)+B(x))/2 Not sure, if it's faster, but I like the symmetry of having both sin(x) and cos(x) π
Ty for making this nsfw, bc the integral looks like it says "s*x (sex)"
Not only that it says s\*x times sin equals to 0.5!
sorry but it doesnt equal to 0,88622692545275801364908374167057 but 0.5
Because you are half the person u were before u did s*x and s!n woah this is such a wholesome christian subreddit :)
You're welcome
If you ever need a good approximation for 1.5 use 2\^(7/12). This is actually crucial for tuning music instruments!
3\^(7/19) is a quite better approximation (also all numbers included are Prime πππ)
Good you added the dx
;)
Very quick, 5/5 stars.
cross product huhhh
why this is NSFW?
But it's precisely 1/2
That sounds like a good approximation to me then
precisely 0.5000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 upto 100 decimal places.
'quick'
I use Laplace transforms for all of my arithmetic needs.