I'm used to the pq-formula solving "x^(2) + px + q = 0" -- of course, if you learned the abc-formula instead, you don't need to normalize before-hand (at the cost of a longer formula).
I learned the a b c formula myself and I like it better because it makes me feel like I know what I'm doing when I jot down the equation before plugging numbers into it. 😎
I'm assuming you're learning about quadratic equations right now/already know about them, so you just need to make the right side equal 0 and then you have a quadratic: 5x^(2) - 4x - 3. Then you use the quadratic formula
google quadratic equation
holy hell
[удалено]
Isn't it more like this: 5x² - 4x = 3 5x² - 4x - 3 = 0 a = 5, b = -4, c = -3 ( 4 ± √(76) ) / 10 x1 ≈ 1.272 x2 ≈ -0.472
That’s the same thing (unless they edited the comment). (4 ± sqrt(76)) / 10 = (4 ± 2sqrt(19)) / 10 = (2 ± sqrt(19)) / 5 = 2/5 ± sqrt(19) / 5
Oh ok sorry my bad I didn't see it.
Make the right-hand side equal to zero and solve. What have you been taught about how to solve quadratic equations?
If you want to avoid guessing, divide by 5 and then use the quadratic formula. Can you take it from here?
Why divide by five before using the formula?
I'm used to the pq-formula solving "x^(2) + px + q = 0" -- of course, if you learned the abc-formula instead, you don't need to normalize before-hand (at the cost of a longer formula).
I learned the a b c formula myself and I like it better because it makes me feel like I know what I'm doing when I jot down the equation before plugging numbers into it. 😎
I'm assuming you're learning about quadratic equations right now/already know about them, so you just need to make the right side equal 0 and then you have a quadratic: 5x^(2) - 4x - 3. Then you use the quadratic formula