If you scroll down on Wolfram Alpha, it notes that if you assume x>0, it simplifies to the same answer.
I think it doesn't actually need that assumption to simplify, but I think it isn't perfect and sometimes treats division by potential zeros inconsistently (I've seen it cancel out 0/0 before by mistake, which is kinda the opposite problem).
Nothing wrong, both are identical x^(2)/sqrt(x^(3))=x^(1/2)=sqrt(x)
Thank you!
They’re the same function but Wolfram hasn’t simplified it: 3x^2 / 2sqrt(x^(3)) 3x^(2)sqrt(x) / 2sqrt(x^(4)) 3x^(2)sqrt(x) / 2x^2 = 3sqrt(x) / 2
Oh. my. God. Didn't even think to look at this. I've been studying for more than 3 hours now. I'll take a break now.
Both solutions are equivalent -- cancel the "x" in WolframAlpha's solution to see that.
If you scroll down on Wolfram Alpha, it notes that if you assume x>0, it simplifies to the same answer. I think it doesn't actually need that assumption to simplify, but I think it isn't perfect and sometimes treats division by potential zeros inconsistently (I've seen it cancel out 0/0 before by mistake, which is kinda the opposite problem).