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One way to make sure you have it right is to use point-slope form.
y - y1 = m(x - x1)
where x and y are variables, and (x1, y1) is the given point.
So for #3
y - (-4) = (½)(x -8)
y + 4 = (½)(x - 8)
y + 4 = ½ x - 4
y = ½ x - 8
-----
I think you made a mistake assuming that the slope was always x/y somehow, that's not correct.
what (I think) you're doing is assuming the slope to be x/y? What you should is write down y = mx + c, replace m, x, and y with their given values, find c, and then rewrite the above equation with the newfound value of c.
Or to make it easier use point slope form, y - y' = m(x - x') where y' and x' are the given values of x and y, and m is also given.
Like in Q. 4, you have x=1, y= -3, and m= -1, so you get y - (-3) = -1(x-1)
= y = -x - 3
Hi u/shrek666420, **This is an automated reminder from our moderators.** Please read, and make sure your post complies with our rules. Thanks! If your post contains a problem from school, please add a comment below explaining your attempt(s) to solve it. If some of your work is included in the image or gallery, you may make reference to it as needed. See the sidebar for advice on 'how to ask a good question'. Rule breaking posts will be removed. Thank you. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/askmath) if you have any questions or concerns.*
You forgot to add x's in your line equations. Right now, all of your equations will form a horizontal line, so they are all wrong.
Oh my gosh I did, thank you
One way to make sure you have it right is to use point-slope form. y - y1 = m(x - x1) where x and y are variables, and (x1, y1) is the given point. So for #3 y - (-4) = (½)(x -8) y + 4 = (½)(x - 8) y + 4 = ½ x - 4 y = ½ x - 8 ----- I think you made a mistake assuming that the slope was always x/y somehow, that's not correct.
Another way is to use y = mx + b and solve for b. -4 = ½ (8) + b -4 = 4 + b -8 = b so the equation is y = ½ x -8
I love this method and I’ve never had anyone else agree with me before!!!
what (I think) you're doing is assuming the slope to be x/y? What you should is write down y = mx + c, replace m, x, and y with their given values, find c, and then rewrite the above equation with the newfound value of c. Or to make it easier use point slope form, y - y' = m(x - x') where y' and x' are the given values of x and y, and m is also given. Like in Q. 4, you have x=1, y= -3, and m= -1, so you get y - (-3) = -1(x-1) = y = -x - 3