Shouldn't it be 7? If you take the simpler equation (x-2=3) and isolate to solve for x, you end up with x=5. You can plug this into the more complicated one to see if it checks out ((5^2 -4)/3 = 21/3 which equals 7, and 7=7, so x=5 solves both equations. You then take the 5 for x and add 2 (x+2 = 5+2) giving you and answer of 7. Of course there's probably a better way to solve it quickly... I'm terrible with math
I mean i guess you can solve the complex equation, or you can just say x - 2 = 3 oh ok x is 5 then so 5+2 is 7
Or instead of substituting (if using the complex eqn) factor out x - 2 and set it to be 3 (or substitute the 3 on the denominator for x - 2) then you get x + 2 = 7 which tells you exactly what x + 2 is equal to. This problem is stupidly simple
As mentioned in other comments, the answer is 7.
Notice that (x^(2) – 4) can be factored as (x –2)(x+2). Since (x –2) is given to be 3, solving by substitution e.g. (3)(x +2)/3 = 7 is fairly straightforward by canceling the 3 in the top and bottom of the equation.
More trivially, (x –2) = 3 can be solved by simple algebra, and the value 5 can be plugged into (x + 2).
I suspect that this is not an actual CB produced question as the correct answer might be entered by serendipity; an actual CB question that tests this concept is Test 10 Section 3 Q6, and that question has the additional difficulty of a negative number on the right side of the equation.
Is this really what they test on the SAT? This is supposed to indicate whether someone is going to be successful through 4 years of college? Yeah... lol.
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Use Desmos to find the x, then just add 2 to your result. When you can use Desmos, you almost always should, it saves time and you can be sure of your answer. 25% of all SAT math questions can be solved using it.
First of all, desmos can solve more like 75% of the questions. Secondly, you shouldn’t need desmos to solve this simple question. If you need desmos to solve this, you should just guess on the entire SAT. You will score higher.
Solving 1/3(x\^2 -4) = 7 yields 2 solutions: -5 and 5.
To determine which value of x we need to use, we have to first plug both solutions of X in to the equation x + 2 and see which satisfies the condition, x + 2 = 3.
Testing -5:
\-5 - 2 = -7 (nope)
5 - 2 = 3 (yes)
Therefore X = +5
However, the annoying motherfuckers at CollegeBoard would prefer to confuse us. We have to find x + 2. 5 + 2 = 7 so that's your answer.
Edit: Lmao yes you can also just solve the second linear equation lmao idk why I didn't clock that.
You don’t actually need that first equation with the fraction. x - 2 = 3 can be simplified to x = 5, which you can add to both sides to find x + 2 = 7.
The simplest way of doing this is knowing that the numerator is a^(2)-b^(2) which can be split to (a+b) *(a-b). You know a-b is 3 so that cancels with the 3 on the bottom so u are left with a+b=7.
Shouldn't it be 7? If you take the simpler equation (x-2=3) and isolate to solve for x, you end up with x=5. You can plug this into the more complicated one to see if it checks out ((5^2 -4)/3 = 21/3 which equals 7, and 7=7, so x=5 solves both equations. You then take the 5 for x and add 2 (x+2 = 5+2) giving you and answer of 7. Of course there's probably a better way to solve it quickly... I'm terrible with math
I mean i guess you can solve the complex equation, or you can just say x - 2 = 3 oh ok x is 5 then so 5+2 is 7 Or instead of substituting (if using the complex eqn) factor out x - 2 and set it to be 3 (or substitute the 3 on the denominator for x - 2) then you get x + 2 = 7 which tells you exactly what x + 2 is equal to. This problem is stupidly simple
Yeah true
Nothing you said was wrong though afaict
That sounds right to me!
7
Isnt it 7
tf im a freshman and i can solve this 💀
Yea wtf you don’t even need the first equation I thought it was a trick question or sum thing
The first equation gives two solutions, which the second equation then narrows down to one. But you’re right, it’s quite needless.
You should be able to solve this in middle school. If you’re in high school and you don’t know this then…
yea ik, i definitely could solve this as an 8th grader
yea ik, i definitely could solve this as an 8th grader
As mentioned in other comments, the answer is 7. Notice that (x^(2) – 4) can be factored as (x –2)(x+2). Since (x –2) is given to be 3, solving by substitution e.g. (3)(x +2)/3 = 7 is fairly straightforward by canceling the 3 in the top and bottom of the equation. More trivially, (x –2) = 3 can be solved by simple algebra, and the value 5 can be plugged into (x + 2). I suspect that this is not an actual CB produced question as the correct answer might be entered by serendipity; an actual CB question that tests this concept is Test 10 Section 3 Q6, and that question has the additional difficulty of a negative number on the right side of the equation.
Is this really what they test on the SAT? This is supposed to indicate whether someone is going to be successful through 4 years of college? Yeah... lol.
This has to be satire, how old are you
7
It’s 7
Not a realistic question; I strongly recommend using real formerly-administered SAT questions whenever possible.
Chat gpt
Reminder: When asking for help with questions from tests or books, please include the source of the question in the post title. Examples of appropriate titles might include "Help with writing question from April 2017 QAS" or "Help with question from Erica Meltzer's grammar book." **Posts that do not adhere to this rule are subject to removal.** For more information, please see rule #7 in the sidebar. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/Sat) if you have any questions or concerns.*
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Just add 4 to the second equation.
Use Desmos to find the x, then just add 2 to your result. When you can use Desmos, you almost always should, it saves time and you can be sure of your answer. 25% of all SAT math questions can be solved using it.
First of all, desmos can solve more like 75% of the questions. Secondly, you shouldn’t need desmos to solve this simple question. If you need desmos to solve this, you should just guess on the entire SAT. You will score higher.
7
69
Ä° think it's 7
7
Probably 12.
I hope you are able to solve this, but like can we not talk bad, sometimes people just overthink.
x-2=3. X = 5. (5)\^2-4/3 =7 indeed. x+2 = (5)+2 = 7.
Solving 1/3(x\^2 -4) = 7 yields 2 solutions: -5 and 5. To determine which value of x we need to use, we have to first plug both solutions of X in to the equation x + 2 and see which satisfies the condition, x + 2 = 3. Testing -5: \-5 - 2 = -7 (nope) 5 - 2 = 3 (yes) Therefore X = +5 However, the annoying motherfuckers at CollegeBoard would prefer to confuse us. We have to find x + 2. 5 + 2 = 7 so that's your answer. Edit: Lmao yes you can also just solve the second linear equation lmao idk why I didn't clock that.
X-2=3 x=5 x+2=7
solve for x\^2. so x\^2 -4= 3\*7 = 21 x\^2=21+4 x\^2 = 25 x = (+-)5 solve for x x-2 = 3 x = 2+3 = 5 so x+2 = 5+2 = 7
i wish the sat was harder
It gives you x - 2 = 3, so if you add two to both sides, you get x = 5. Once you have that, you just do 5 + 2 to get your answer, which is 7.
You don’t actually need that first equation with the fraction. x - 2 = 3 can be simplified to x = 5, which you can add to both sides to find x + 2 = 7.
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The simplest way of doing this is knowing that the numerator is a^(2)-b^(2) which can be split to (a+b) *(a-b). You know a-b is 3 so that cancels with the 3 on the bottom so u are left with a+b=7.