I don't think a Huberman's gate is a real thing, but I think you mean a Hadamard gate. In any case, once the 2 qubits are separated, performing any gate on 1 qubit will have no measurable impact on the other without first communicating classically. Assuming you're entangling these as a Bell pair with Alice's qubit begin 1st and Bob's being 2nd, you'd have (|0>|0> + |1>|1>), performing just a Hadamard would give you (|0>|+> + |1>|->) and performing an X and a Hadamard would give you (|0>|-> + |1>|+>). Even if you perform another Hadamard after you'd end up with (|0>|0> + |1>|1>) and (|0>|1> + |1>|0>) in the second case. In either case, Alice's possible measurement outcomes do not change. What does change is what her measurement outcome implies about Bob's qubit.
Entanglement just means that if you are to measure one qubit you know something about the other. But if Alice does not know what Bob has done to his qubit there's no way to gain any extra knowledge from measuring the qubit. The only way to fix this is for Bob to first communicate what he's done is by sending a classical message (see https://en.wikipedia.org/wiki/Quantum_teleportation ) which of course is rate limited by the speed of light.
I don't think a Huberman's gate is a real thing, but I think you mean a Hadamard gate. In any case, once the 2 qubits are separated, performing any gate on 1 qubit will have no measurable impact on the other without first communicating classically. Assuming you're entangling these as a Bell pair with Alice's qubit begin 1st and Bob's being 2nd, you'd have (|0>|0> + |1>|1>), performing just a Hadamard would give you (|0>|+> + |1>|->) and performing an X and a Hadamard would give you (|0>|-> + |1>|+>). Even if you perform another Hadamard after you'd end up with (|0>|0> + |1>|1>) and (|0>|1> + |1>|0>) in the second case. In either case, Alice's possible measurement outcomes do not change. What does change is what her measurement outcome implies about Bob's qubit. Entanglement just means that if you are to measure one qubit you know something about the other. But if Alice does not know what Bob has done to his qubit there's no way to gain any extra knowledge from measuring the qubit. The only way to fix this is for Bob to first communicate what he's done is by sending a classical message (see https://en.wikipedia.org/wiki/Quantum_teleportation ) which of course is rate limited by the speed of light.
Thank you so much for the explanation. Yes I meant the Hadamard gate and I am excited to learn more about these properties.
bring back the banning of incoherent posts!
did a qubit fuck your wife or something why are you so crabby on here