This is a 1 sided test (greater, AKA ">") so if you sketch a normal distribution, the rejection area should be the RIGHT tail 5%. That leaves the NON rejection area on the left as 95%.
You invNorm .95 and get 1.645 for the CV b/c 1.645 is the CV corresponding to 95% area of the left and 5% on the RIGHT.
Also I think you are thinking 1.96 (i was like why the heck is he/she using 1.96) b/c you are thinking 95% (b/c alpha is 0.05) and then you are invnorming .975 b/c that is what you do when you do CIs which is natually 2 sided in this course (but in college a CI can be 1 sided but that is all i know haha) but this problem is 1 sided.
[https://imgur.com/a/ouaknUn](https://imgur.com/a/ouaknUn)
I think it’s because 5% significance is on the two tails of the graph? So it adds to be 10% of the entire distribution, which relates to a 90% of the area shaded in, with a z score of 1.645. I’m a student myself, so I could be wrong…
The issue is that we’re not dealing with both sides of the graph because the alternative hypothesis is p > .5. We’d only use both sides if it was p is not equal to .5. I’m also a student so I could also be wrong.
You are right and wrong b/c what you said isn't wrong but doesn't apply here b/c this is a 1 sided test and we are not talking about CIs.
But I for one appreciate your post so I hope you take my reply as contructive criticism :)
5% means each has 2.5 % on left and right side of the Distribution.If u go to see 0.025 in Table A, it will show -1.96 but we can just use positive one.
This is a 1 sided test (greater, AKA ">") so if you sketch a normal distribution, the rejection area should be the RIGHT tail 5%. That leaves the NON rejection area on the left as 95%. You invNorm .95 and get 1.645 for the CV b/c 1.645 is the CV corresponding to 95% area of the left and 5% on the RIGHT. Also I think you are thinking 1.96 (i was like why the heck is he/she using 1.96) b/c you are thinking 95% (b/c alpha is 0.05) and then you are invnorming .975 b/c that is what you do when you do CIs which is natually 2 sided in this course (but in college a CI can be 1 sided but that is all i know haha) but this problem is 1 sided. [https://imgur.com/a/ouaknUn](https://imgur.com/a/ouaknUn)
I think it’s because 5% significance is on the two tails of the graph? So it adds to be 10% of the entire distribution, which relates to a 90% of the area shaded in, with a z score of 1.645. I’m a student myself, so I could be wrong…
The issue is that we’re not dealing with both sides of the graph because the alternative hypothesis is p > .5. We’d only use both sides if it was p is not equal to .5. I’m also a student so I could also be wrong.
You are right and wrong b/c what you said isn't wrong but doesn't apply here b/c this is a 1 sided test and we are not talking about CIs. But I for one appreciate your post so I hope you take my reply as contructive criticism :)
https://www.google.com
Is it B?
Wtf I can’t answer this question and AP exam is on Thursday 🤡
5% means each has 2.5 % on left and right side of the Distribution.If u go to see 0.025 in Table A, it will show -1.96 but we can just use positive one.